GRE math thinking skills 1

GRE tests your logical skills as well as your knowledge of math concepts.  To score high, you need to remember various formulas, theorems. Also you need to master critical problem-solving skills.

 I am going to take you through one problem-solving skill –

 Problem analysis with a diagram

Take this problem .

If you follow approach 1.

 You will use many formulas and theorems. You will get an answer, but it will take more time.

 If you follow approach 2.

You will minimize the number of formulas used. You will use your logical skills and reduce complex computation. You will solve questions faster.

In GRE time-taken per question is the key. If you solve questions in less than 30 seconds, then you will have more time in the bank to solve harder questions. You will also be able to complete the section in the allotted time.

Can logic be taught?

Yes!  Logic can be taught. If the tutor teaches you reasoning skills and demonstrates those skills on a wide range of problems, your thinking will get re-oriented. You will be able to solve questions using more than one approach.

 I feel Logic is best taught in a tutor-driven class, not through generic videos

If you need help in GRE, here are my details

My contact link is here:

LinkedIn profile : https://www.linkedin.com/in/georgeanand/

Facebook learning group: https://www.facebook.com/groups/semanticsgre

Now let us understand both the approaches.

Approach 1

This approach involves formulae/theorem...

Area of square ABCD = side²

Side = 8. Hence area =64

F and E are midpoints of the respective sides. AB=AD=8

 Hence AF=FB=4 and AE=ED=4

 Triangle AEF, Triangle BFC and Triangle EDC are right angled triangles. Hence we can use Pythagoras theorem

This approach was time consuming. Also, This approach involves lots of calculation.

Approach 2 - faster approach

 

When you encounter geometry problems, look at the picture for few seconds.

Can you observe a square and 4 triangles?

Spend time observing the pictures and look for clues.

The area of shaded portion is equal to the area of the square – (sum of the area of the 3 triangles).

This approach requires you to know the area of the triangle = 0.5 x base x height.

Now let’s analyze the figure. F and E are the midpoints

 The sides of the square are 8

 Area of triangle AEF = 0.5x4x4 = 8

 Area of triangle EDC = 0.5x4x8 = 16

 Area of triangle FBC = 0.5x8x4 = 16

 Area of square =64

 Area of shaded region = 64- 16-16-8 =24

 This approach is far easier and involves less calculation.

 So always use logic to arrive at answers faster